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Is TSS score linear?
If you are riding absolutely perfect, will TSS increase at the same rate? IE:, if you rode for an hour and racked up 50 tss points, would 2 hours yield 100 tss points?
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Yes, if you maintained the same Intensity Factor (IF) across both rides.
But as Scott said, all TSS are not created equal, meaning it is a mathematical model that is meant to approximate training stress. With practice, you will see that there are a whole lot of ways to accumulate say 200 TSS points in a ride through variations of intensity and duration.
At the end, they all 'cost' you the same TSS, but some of those rides will leave you significantly more fatigued than others, i.e. the model is not perfect.
The basic calculation that's done is that you do some averaging on the power to give you a "rolling" IF for any given moment. The IF is raised to a higher power to regulate how much that "second of work" costs you in TSS points, where higher intensity stuff costs a lot more points than lower intensity ones. Then you simply add up the points earned each second. So, as a result, as long as you hold IF constant, it is linear with time. A scaling factor is applied so that 100 points = 1 hour at FTP
To give the formula in qualitative terms:
To give an example where the TSS model fails, consider the idea of doing a ~3 hour ride at around 0.8 IF (constant). This will simulate the number of TSS points that's pretty close to ideal for a HIM ride of about 180. Hard, but not crazy. Now consider the theoretical possiblity of riding at 100% FTP for 108 straight minutes, which would also give you 180 TSS points. By definition, this can't even be done, since FTP is supposed to be how hard you could ever possibly ride for 60 minutes before dropping out of the saddle in exhaustion. :-)
That's a great example William. I always had to resort to trying to get people to examine their historical data and just think about how different rides at different TSS' made them 'feel', yours illustrates the point far better!